tag:blogger.com,1999:blog-5871184605628305545.post2131151891479181685..comments2013-05-25T03:36:33.414-07:00Comments on Puzzled: Sphere and the Heat SourceAnonymoushttp://www.blogger.com/profile/02364548875097103884noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-5871184605628305545.post-63612262235858534382012-08-10T11:46:12.026-07:002012-08-10T11:46:12.026-07:00Correct Rik, very well explainedCorrect Rik, very well explainedAnonymoushttps://www.blogger.com/profile/02364548875097103884noreply@blogger.comtag:blogger.com,1999:blog-5871184605628305545.post-42385080631067198622012-07-14T14:13:02.513-07:002012-07-14T14:13:02.513-07:00consider a point A on a greater circle and A' ...consider a point A on a greater circle and A' its diametrically opp. point... now let T(x) gives temp of a point x... then consider f(x) = T(x)- T(x') on [A,A'] along the greater circle... then f(x) changes sign in its range as f(A) = - f(A')... so by mean value theorem there exists a point P st f(P) = 0 i.e. temp of P and its opp. point P' are same...Rikhttps://www.blogger.com/profile/16765576918216443372noreply@blogger.com