You need to guess 3 natural numbers x, y, z. You can be provided with two weighted average sums (i.e) ax+by+cz with any coefficients a,b,c (i.e.) you give any a,b,c i ll provide you with ax+by+cz, however this freedom is only allowed twice.

This question is very similar to the question "Guess the polynomial"

This question is very similar to the question "Guess the polynomial"

1st choice a=b=c=1 to get their sum s = x+y+z .... then use s as base (valid as s>x,y,z) and get the decimal representation of (xyz) base s ... that is 2nd choice is a=s^2, b=s, c=1 ..... then extract xyz from the decimal representation to base s (same process as finding binary no, divide by s and take the remainders)....

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